A train moves from one station to another in 2 hours time its speed time graph during the. motion is shown in figure determine the maximum acceleration also calculate the distance coveredduring thrle time interval from 0.75 hours to 1 hours

Maximum acceleration will occur in the region with maximum slope.

From the given curve region CD is having the maximum curve.

Thus, maximum acceleration=

change in distance/change in velocity

60-20/0.25

=160

Now, total area under the curve between 0.75 to 1.00 hrs is given by

(1/2×0.25×40)+(20×0.25) =10k

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(i) Since acceleration is the rate of change of velocity, it is given by the slope of the velocity time curve. Here the slope is greatest between ¾ and 1 hour.

Change in the velocity in this interval = (60-20) km h ⁻¹

.·. Acceleration in this interval = (60-20)/(1-(3/4)) km h ⁻²

= 160 km h ⁻²

(ii) Distance travelled during this interval is given by s = ut + 1/2 at²

= 20 (1/4) + 1/2(160)(1/4)²

= 10 km

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Explanation:

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Explanation:

I don't know the answer but same question I also mentioned no answer

Explanation:

Maximum acceleration will occur in the region with maximum slope.

From the given curve region CD is having the maximum curve.

Thus, maximum acceleration=

change in distance

change in velocity

=

0.25

60−20

=160

Now, total area under the curve between 0.75 to 1.00 hrs is given by

(

2

1

×0.25×40)+(20×0.25)=10km

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Explanation:

The compound K2O2 also exists. A chemist can determine the mass of K in a sample of known mass that consists of either pure K2O or pure K2O2. From this information, can the chemist answer the question of which compound is in the sample? Indicate yes or no, and explain.

Explanation:

Where is the figure dude!??

Explanation:time = speed / distance

From the given fig, we can find that maximum acceleration is found when the train moves from position c to d.

Speed between c and d=60-20=40kmph

Time interval between c and d=0.25hr

so, maximum acceleration=40/0.25

=160kmph².

Maximum acceleration will occur in the region with maximum slope.

From the given curve region CD is having the maximum curve.

Thus, maximum acceleration=

change in distance

change in velocity

=

0.25

60−20

=160

Now, total area under the curve between 0.75 to 1.00 hrs is given by

(

2

1

×0.25×40)+(20×0.25)=10km

Explanation:

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answer:

sound travels fasts in gases and slow in liquid in comparison to gases

answer:

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